5x^2-9x+7=0

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Solution for 5x^2-9x+7=0 equation:


Simplifying
5x2 + -9x + 7 = 0

Reorder the terms:
7 + -9x + 5x2 = 0

Solving
7 + -9x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
1.4 + -1.8x + x2 = 0

Move the constant term to the right:

Add '-1.4' to each side of the equation.
1.4 + -1.8x + -1.4 + x2 = 0 + -1.4

Reorder the terms:
1.4 + -1.4 + -1.8x + x2 = 0 + -1.4

Combine like terms: 1.4 + -1.4 = 0.0
0.0 + -1.8x + x2 = 0 + -1.4
-1.8x + x2 = 0 + -1.4

Combine like terms: 0 + -1.4 = -1.4
-1.8x + x2 = -1.4

The x term is -1.8x.  Take half its coefficient (-0.9).
Square it (0.81) and add it to both sides.

Add '0.81' to each side of the equation.
-1.8x + 0.81 + x2 = -1.4 + 0.81

Reorder the terms:
0.81 + -1.8x + x2 = -1.4 + 0.81

Combine like terms: -1.4 + 0.81 = -0.59
0.81 + -1.8x + x2 = -0.59

Factor a perfect square on the left side:
(x + -0.9)(x + -0.9) = -0.59

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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